巧用MySQL InnoDB引擎锁机制解决死锁问题
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案例如下: 在使用Show innodb status检查引擎状态时,发现了死锁问题: *** (1) TRANSACTION: TRANSACTION 0 677833455, ACTIVE 0 sec, process no 11393, OS thread id 278546 starting index read mysql tables in use 1, locked 1 LOCK WAIT 3 lock struct(s), heap size 320 MySQL thread id 83, query id 162348740 dcnet03 dcnet Searching rows for update update TSK_TASK set STATUS_ID=1064,UPDATE_TIME=now () where STATUS_ID=1061 and MON_TIME*** (1) WAITING FOR THIS LOCK TO BE GRANTED: RECORD LOCKS space id 0 page no 849384 n bits 208 index `PRIMARY` of table `dcnet_db/TSK_TASK` trx id 0 677833455 lock_mode X locks rec but not gap waiting Record lock, heap no 92 PHYSICAL RECORD: n_fields 11; compact format; info bits 0 0: len 8; hex 800000000097629c; asc b ;; 1: len 6; hex 00002866eaee; asc (f ;; 2: len 7; hex 00000d40040110; asc @ ;; 3: len 8; hex 80000000000050b2; asc P ;; 4: len 8; hex 800000000000502a; asc P*;; 5: len 8; hex 8000000000005426; asc T&;; 6: len 8; hex 800012412c66d29c; asc A,f ;; 7: len 23; hex 75706c6f6164666972652e636f6d2f6 8616e642e706870; asc xxx.com/;; 8: len 8; hex 800000000000042b; asc +;; 9: len 4; hex 474bfa2b; asc GK +;; 10: len 8; hex 8000000000004e24; asc N$;;
TRANSACTION 0 677833454, ACTIVE 0 sec, process no 11397, OS thread id 344086 updating or deleting, thread declared inside InnoDB 499 mysql tables in use 1, locked 1 3 lock struct(s), heap size 320, undo log entries 1 MySQL thread id 84, query id 162348739 dcnet03 dcnet Updating update TSK_TASK set STATUS_ID=1067,UPDATE_TIME=now () where ID in (9921180) *** (2) HOLDS THE LOCK(S): RECORD LOCKS space id 0 page no 849384 n bits 208 index `PRIMARY` of table `dcnet_db/TSK_TASK` trx id 0 677833454 lock_mode X locks rec but not gap Record lock, heap no 92 PHYSICAL RECORD: n_fields 11; compact format; info bits 0 0: len 8; hex 800000000097629c; asc b ;; 1: len 6; hex 00002866eaee; asc (f ;; 2: len 7; hex 00000d40040110; asc @ ;; 3: len 8; hex 80000000000050b2; asc P ;; 4: len 8; hex 800000000000502a; asc P*;; 5: len 8; hex 8000000000005426; asc T&;; 6: len 8; hex 800012412c66d29c; asc A,f ;; 7: len 23; hex 75706c6f6164666972652e636f6d2f6 8616e642e706870; asc uploadfire.com/hand.php;; 8: len 8; hex 800000000000042b; asc +;; 9: len 4; hex 474bfa2b; asc GK +;; 10: len 8; hex 8000000000004e24; asc N$;;
RECORD LOCKS space id 0 page no 843102 n bits 600 index `KEY_TSKTASK_MONTIME2` of table `dcnet_db/TSK_TASK` trx id 0 677833454 lock_mode X locks rec but not gap waiting Record lock, heap no 395 PHYSICAL RECORD: n_fields 3; compact format; info bits 0 0: len 8; hex 8000000000000425; asc %;; 1: len 8; hex 800012412c66d29c; asc A,f ;; 2: len 8; hex 800000000097629c; asc b ;;
ID:主键;
分析,涉及的两条语句应该不会涉及相同的TSK_TASK记录,那为什么会造成死锁呢?
要点如下:
如语句UPDATE TSK_TASK SET UPDATE_TIME = NOW() WHERE ID > 10000会锁定所有主键大于等于1000的所有记录,在该语句完成之前,你就不能对主键等于10000的记录进行操作;
假设“update TSK_TASK set STATUS_ID=1067,UPDATE_TIME=now () where ID in (9921180)”几乎同时执行时,本语句首先锁定簇索引(主键),由于需要更新STATUS_ID的值,所以还需要锁定KEY_TSKTASK_MONTIME2的某些索引记录。
先查出符合条件的ID:select ID from TSK_TASK where STATUS_ID=1061 and MON_TIME < date_sub(now(), INTERVAL 30 minute);然后再更新状态:update TSK_TASK set STATUS_ID=1064 where ID in (….) 至此,死锁问题彻底解决 |
