判断ICQ是否在线的代码
点击次数:23 次 发布日期:2008-11-26 02:20:32 作者:源代码网
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<? function get_status($uin) { $fp = fsockopen ("wwp.icq.com", 80, &$errno, &$errstr, 30); if(!$fp) { echo "$errstr ($errno)<br> "; } else { fputs($fp, "GET /scripts/online.dll?icq=$uin&img=5 HTTP/1.0 "); $do = "yes"; while(!feof($fp)) { $line = fgets ($fp,128); $do = ($do == "yes")?"yes":(eregi("^GIF89", $line))?"yes":"no"; //echo $line; if($do == "yes") { if(ereg("@", $line)) { return "online"; } elseif(ereg("醱", $line)) { return "offline"; } elseif(ereg("S", $line)) { return "disabled"; } } } fclose($fp); } return "unknown!"; } $uin="72485936"; // sonymusic 的ICQ,呵呵。 echo get_status($uin); // offline ?> 源代码网供稿. |
